Wednesday, 15 June 2016

Creating art with microbes on an agar plate


Dr CharuSudan 

Who says scientists can't be artists?

Check out the creativity at the Agar Art competition, 2016, held by the American Society for Microbiology. 117 participants from 26 countries competed for the awards, creating amazingly beautiful and colourful microbial cultures on agar plates.

And the winners are........

Follow the link below
Art with microbes and an agar plate


Thursday, 26 May 2016

A century's progression from the chromosomal theory of inheritance

Dr CharuSudan


A hundred years ago, in 1916, CB Bridges published a paper in the journal GENETICS, describing  the occurrence of meiotic non-disjunction in the fruit fly Drosophila.
C.B. BRIDGES, “NON-DISJUNCTION AS PROOF OF THE CHROMOSOME THEORY OF HEREDITY(concluded),” GENETICS, 1:107-63, 1916.

He presented his results in the form of meticulous drawings illustrating the karyotypes of various flies. Some of the flies expressed sex-linked phenotypes which were against the pattern exhibited by X-linked gene. When their chromosomes were analysed, they showed Non-disjunction of the X chromosomes. This was the first evidence for non-disjunction of chromosomes.

More important was the fact that behaviour, or in this case, misbehaviour (error in the separation) of a specific chromosome ie the X chromosome was associated with unusual inheritance of certain phenotypic traits in the fruit fly. 

This provided confirmatory evidence for the the chromosomal theory of inheritance; the theory that says that genes are located on chromosomes.    


Check out this article in the May 2016 issue of  the journal 'The Scientist' . 

Picturing Inheritance, 1916

This year marks the centennial of Calvin Bridges’s description of nondisjunction as proof that chromosomes are vehicles for inheritance. 




Sunday, 24 April 2016

MSc Biotech Entrance Exam by JNU - Analysis of Trends

Dr CharuSudan

JNU CBEE 2016 (Combined Biotechnology  Entrance Exam-2016)

The combined entrance exam for Biotechnology, is conducted by Jawaharlal Nehru University 
Date of exam: 19th May, 2016
Timing: 9AM to 12PM

Pattern of the question paper
The type of questions will be Multiple Choice Questions (MCQs). The question paper is divided into two parts
Part-A :  Total 60 questions. All compulsory. Each correct answer gets 1 mark each. Each wrong answer has a negative marking of  ½ (half) mark. The questions are from 10+2 level. Subjects are  Physics, Chemistry, Mathematics and Biology. Total marks for Part A will be 60.
Part-B:  There are total 100 questions, out of which 60 questions need to be attempted. Each correct answer is worth 3 marks. Wrong answer has a negative marking of 1 mark each. The questions are from Bachelor’s level. Total marks for Part B will be 180 marks (60 questions x 3 marks)

Analysis of the question paper for the past 3 years (2013-2015)


  • All questions in part A are compulsory, therefore it is important that students are well prepared  in all the 4 subjects (physics, chemistry, maths and biology) till the 10+2 level.  
  • In 2015,, the weightage given to maths has increased  significantly, both for part A and B. In the 2015 paper, out of the maths questions, at least 3-4 questions are from probability and binomial expansion and 2-3 from Statistics. All biology students must be good in these areas, since they will also be  applied to solve numericals based on genetics.   
  • Maths is also essential for many calculations in molecular biology and RDT, such as concentration and volume calculations for buffer and chemicals, calculation of cell generation times, serial dilutions, molarity etc .  

Students of biotechnology cannot afford to fear or ignore maths.

  • Then in part B, 60 questions need to the attempted, out of which only 55 questions are from biology. Even if the student attempts all biology-based questions, at least a few non-biology based questions will need to be attempted. 
  • It may be useful to concentrate on chemistry at the bachelor’s level, as around 17 questions come from chemistry. Also, a sound knowledge of chemistry will be extremely helpful when pursuing a career in biotechnology, biochemistry etc.  

Hope this helps. All the best for your exams

Tuesday, 23 February 2016

Genetics-Solved Problem from Bacterial Genetic Recombination

Dr CharuSudan


Question: A co-transduction experiment was performed to decipher the linear order of 4 genes: w, x, y and z. Three sets of experiments were performed. In set 1, the Transductants were selected for gene w, in set 2, gene x was selected and in set-3, gene y was selected. In each set, the transductants were screened for co- transduction of the other markers.
Based on the frequencies of co-transduction,  identify the most likely order in the genome.                                                                          

1. w, x, y, z     2. x y z w         3. y z w x         4. w z x y


                                                                                     Based on question from CSIR-NET (2014) 
For answer and analysis





Sunday, 21 February 2016

GENETICS FOR CSIR-NET, GATE, MSc ENTRANCE


GENETICS: PROBLEMS, SOLUTIONS AND ANALYSIS-II

Dr CharuSudan

Today we deal with a very simple question.

Q1: Given a genotype, AABbccDdEe, how many different types of gametes can it form. 
A. 3
B. 4
C. 5
D. 8

Q2: What are the different combinations of gametes formed by the above genotype

Saturday, 20 February 2016

GENETICS FOR CSIR-NET, GATE AND MSc ENTRANCE


 Genetics: Problems, Solution and Analysis-I


Dr CharuSudan



Q1: What are the different pairing possibilities in an autotetraploid during meiosis
A. Two bivalents
B. one quadrivalent                                             
C. One univalent+ One trivalent                                      
D. All the above


Q2: Which of the above pairings can lead to production of diploid gametes?
1. Only A        2. B and C       3. A and C       4. A and B

Solution at: